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Jim Hanks
02-04-2016, 02:03 PM
I was noodling on the piano today and came up with the following challenge:
1. Compose a progression of three chords.
2. Each chord must consist of 4 notes playable on ukulele (in other words, each string plays one of the notes)
3. Among the 3 chords, all 12 notes of the chromatic scale must be used exactly once.
4. It has to sound "musical" ;-)

The easiest progression that meets the first 3 criteria would be this:
0101 1212 2323
Not very musical though. ;-)

Here's my first attempt:
0055 1311 6677
C69 Ebsus2sus4 F#7sus4

What can you come up with?

Ukejenny
02-05-2016, 04:45 AM
BM7 3322 A# D# F# B
G7sus4 0213 G C F D
Amaj7 1100 G# C# E A

Musicality score, out of 10, probably about a .8 - needs some bridging chords.

I like the chord progression, BM7, E7, G7sus4, Amaj7. Flows a little better. Maybe a 3 out of 10 on the musicality scale.

Jim Hanks
02-05-2016, 09:21 AM
I like it!

TheCraftedCow
02-06-2016, 07:44 PM
can I copy something of Schoenberg or does it have to be original? I have a daughter who is a concert pianist. She also plays with a SKA group. I shall ask her if she has any 12 tone row SKA pieces. 23 of her chromosomes are from me...........

Jim Hanks
02-07-2016, 02:48 AM
Does not have to be original. I am aware of "12 tone row" concept but have pretty much dismissed it as the few examples I've heard didn't sound "melodic" enough for me to want to listen twice. :p Something about the chordal approach sounds more promising to me. If you can pull something "musical" out of Schoenberg I'd love to hear it. :)

Here's another one:
0002 CMaj7 gceb
2224 Dmaj7 adf#c#
1311 Ebsus2sus4 g#d#fa#

pluck
02-08-2016, 10:23 AM
The easiest progression that meets the first 3 criteria would be this:
0000 1111 2222
Not very musical though. ;-)


Hmm, I don't think this is true. This includes two A's and zero D#'s.

Three consecutive Dim7ths should do it though.

Jim Hanks
02-08-2016, 02:08 PM
Hmm, I don't think this is true. This includes two A's and zero D#'s.

Three consecutive Dim7ths should do it though.
Doh! You're exactly right! I'll fix the original post. Thanks for the catch.